The moment of inertia of a uniform thin rod of mass m and length l about two axis PQ and RS passing through centre of rod C and in the plane of the rod are I PQ and I RS respectively. Then I PQ + I RS is equal to
(A) ml2 / 3
(B) ml2 / 2
(C) ml2 / 4
(D) ml2 / 12
Correct option: (D) ml2 / 12
Explanation:
The MI of rod about axis PQ figure(a) and MI of rod about axis P Q figure (b) are same by symmetry.
by perpendicular axis theorem.
