A car is going at a speed of 21.6 km/hr when it encounters a 12.8 m long slope of angle 30° (figure 6-E5). The friction coefficient between the road and the tyre is 1/2√ 3. Show that no matter how hard the driver applies the brakes, the car will reach the bottom with a speed greater than 36 km/hr. Take g = 10 m/* 2.
Hardest brake means maximum force of friction is developed between car’* type & road. Max frictional force = μR From the free body diagram
Hence how hard the driver applies the brakes, that car reaches the bottom with least velocity 36km/h.
Hence how hard the driver applies the brakes, that car reaches the bottom with least velocity 36km/h.