+2 votes
in JEE by kratos

Two particles P and Q start their journey simultaneously from point A. P moves along a smooth horizontal wire AB. Q moves along a curved smooth track on the inner surface. Q has sufficient velocity at A to reach B always remaining in contact with the curved track. At A, the horizontal component of velocity of Q is same as the velocity of P along the wire. The plane of motion is vertical. If t1 , t2 , are times taken by P and Q respectively to reach B then (Curve is semicircle and AB is diameter)

(A) t1 = t2

(B) t1 > t2

(C) t1 < t2

(D) none of these

1 Answer

+1 vote
by kratos
 
Best answer

Correct option: (B) t1 > t2

Explanation:

The horizontal component of velocity of Q will increase and become maximum at the top ; and will again become same at B. Because of its greater horizontal velocity the particle Q will reach B earlier than P

∴ P t1 > t2

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