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A force vector F=(7 – 2x + 3x^2) N is applied on 2 kg mass which displaces it from x = 0 to x = 5m.

+3 votes
in JEE by kratos

A force vector F=(7 – 2x + 3x2) N is applied on 2 kg mass which displaces it from x = 0 to x = 5m. Magnitude of work done in joule is -

(A) 70

(B) 270

(C) 135

(D) 115

1 Answer

+6 votes
by kratos
 
Best answer

Correct option (C) 135

Explanation:

(7 -2x +3x2)dx = 135

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