+2 votes
in JEE by kratos

A 500 g block P rests on a frictionless horizontal table at a distance of 400 mm from a fixed pin O . The block is attached to pin O by an elastic cord of constant k = 100N/m and of undeformed length 900 mm . If the block is set in motion perpendicularly as shown in figure. The speed in the begining is such that the distance from O to the block P will reach the maximum value of 1.2 m. (assume there is no loss in energy due to jerk)

(A) Speed of projection is 4.5 m/*

(B) Speed of block when OP = 1.2 m is 2m/*.

(C) The radius of curvature of the path of the block when OP = 1.2 m is 3.75 cm

(D) The radius of curvature of the path of the block when OP = 1.2 m is 1.2 m

1 Answer

+2 votes
by kratos
 
Best answer

Correct option: (A, C)

Explanation:

By conservation of angular momentum

0.5 × V × 0.4 = 0.5 × u × 1.2 v = 3u

also by energy conservation

So v = 3u

= 3 × 1.5

= 4.5

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