*Correct option: (A) p, (B) p, (C) q, (D) r**
Explanation:
The minimum horizontal force required to push the two block system towards left
= 0.2 × 20 × 10 + 0.2 × 10 × 10 = 60.
Hence the two block system is at rest. The FBD of both of blocks is as shown. The friction force f and normal reaction N for each block is as shown.
Hence magnitude of friction force on both blocks is 20 N and is directed to right for both blocks. Normal reaction exerted by 20 kg block on 10 kg block has magnitude 40 N and is directed towards right. Net force on system of both blocks is zero.