+3 votes
in JEE by kratos

Find the minimum value of e(2x2-2x + 1)sin2 x.

1 Answer

+1 vote
by kratos
 
Best answer

2x2 - 2x + 1 = 2(x - 1/2)2 + 1/2

minimum value of 2x2 - 2x + 1 is 1/2 and minimum value of sin2x is 0

minimum value of e (2x2 -2x 1)sin2 x is 1

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