+2 votes
in JEE by kratos

A cylindrical block of wood (density = 650 kg m–3), of base area 30cm2 and height 54 cm, floats in a liquid of density 900 kg m–3. The block is depressed slightly and then released. The time ** of the resulting oscillations of the block would be equal to that of a simple pendulum of length (nearly) :

(1) 52 cm

(2) 65 cm

(3) 39 cm

(4) 26 cm

1 Answer

+3 votes
by kratos
 
Best answer

Correct option (3) 39 cm

Explanation:

mg = FB

h = Length of block immerged in water

650 × A × 54 × 10–2g = 900 × A × hg

h = 0.39m = 39 cm.

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