+2 votes
in JEE by kratos

One end of light inelastic string is tied to a helium filled balloon and its other end is tied to bottom of a water filled container at point O. The container **** on a fixed horizontal surface and is pulled horizontally towards right with constant horizontal acceleration of magnitude a. Assuming no relative motion of balloon and water with respect to container, the string will be inclined with vertical line passing through O by an angle. (g is acceleration due to gravity)

(A) θ = tan–1a/g and string will be on right of vertical line passing through O.

(B) θ= tan–1 g/a and string will be on right of vertical line passing through O.

(C) θ = tan–1 a/g and string will be on left of vertical line passing through O.

(D) θ= tan–1 g /a and string will be on left of vertical line passing through O.

1 Answer

+3 votes
by kratos
 
Best answer

Correct option- (A) = tan–1 a/g and string will be on right of vertical line passing through O.

Explanation:-

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