+2 votes
in Chemistry by kratos

For the equilibrium, A(g) B(g), ⇋ ΔH is –40 kJ/mol. If the ratio of the activation energies of the forward (Ef ) and reverse (Eb ) reactions is 2/3 then :

(1) Ef = 80 kJ/mol; Eb = 120 kJ/mol

(2) Ef = 60 kJ/mol; Eb = 100 kJ/mol

(3) Ef = 30 kJ/mol; Eb = 70 kJ/mol

(4) Ef = 70 kJ/mol; Eb = 30 kJ/mol

1 Answer

+5 votes
by kratos
 
Best answer

Correct option (1) Ef = 80 kJ/mol; Eb = 120 kJ/mol

Explanation:

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