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The solution of the differential equation ydx – (x + 2y^2)dy = 0 is x = f(y). If f(–1) = 1, then f(1) is equal to :

+2 votes
in JEE by kratos

The solution of the differential equation ydx – (x + 2y2)dy = 0 is x = f(y). If f(–1) = 1, then f(1) is equal to :

(1) 4

(2) 3

(3) 1

(4) 2

1 Answer

+4 votes
by kratos
 
Best answer

Correct option (2) 3

Explanation:

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