Question

The equation of the plane containing the lines (x - 4)/1 = 9y + 1)/1 = (z - 0)/-1 and 4x – y +5z – 7 = 0 = 2x – 5y – z – 3 is ax + by + cz – 2 = 0, then a + b – c is equal to

(a) 0

(b) 1

(c) 2

(d) 4

Answer 1

Correct option (a)

Explanation:

Equation of plane passing through the intersection of planes 4x – y + 5z – 7 = 0 2x – 5y – z – 3 = 0 is (4x – y + 5z – 7) + λ(2x – 5y – z – 3) = 0 Plane passes through (4, – 1, 0), therefore O = – 1 Therefore, equation of plane is x + 2y + 3z – 2 = 0