On the basis of the information available from the reaction 4/3 Al + O2 *→ 2/3 Al2 O3,ΔG = -827 kJmol-1 of O2, the minimum e.m.f.*required to carry out electrolysis of Al2O3 is (F = 96500 C mol–1)
(a) 4.28 V
(b) 6.42 V
(c) 8.56 V
(d) 2.14 V
Correct option: (d) 2.14 V
Explanation:
Number of electrons involved is 4 ( 2/3 x 6 = 4)
