1 mol of N2 and 3 mol of H2 are placed in a closed container at a pressure of 4 atm. The pressure falls to 3 atm at the same temperature when the following equilibrium is attained
N (g) + 3H2 (g)⇌2 NH2 (g) 3 .
The Kp for the dissociation of NH3 is
Correct option: (b)
Explanation:
Total *****,
1 – x + 3 – 3x + 2x = 4 – 2x = 3 (given)
( Since, 4 ***** = 4 atm given)
∴ x = 0.5
Kp for dissociation of NH3
= 0.5 × (1.5)3 atm2
