Let f(x) = sin x; g(x) = x2 and h(x) = log x. If u (x) = h (f (g (x))), then d2u/dx2 is
(A) 2 cos3 x
(B) 2 cot x2 – 4x2 cosec2 x2
(C) 2x cot x2
(D) –2 cosec2 x
Correct option (B) 2 cot x2 – 4x2 cosec2 x2
Explanation:
u(x) = h(f (g(x))) = h(f(x2 )) = h (sin x2 ) = log sin x2
Hence u' (x) = 2 x cot x2 and
u(x) = 2 cot x2 – 4x2 cosec2 x2 .