When CH2 = CH – COOH is reduced with LiAlH4 , the compound obtained will be (a) CH3 – CH2 – COOH (b) CH2 = CH – CH2OH (c) CH3 – CH2 – CH2OH (d) CH3 – CH2 – CHO.
(b) : LiAlH4 is a strong reducing agent, it reduces carboxylic group into primary alcoholic group without affecting the basic skeleton of compound.
