In the YDSE apparatus shown in the fig ∆x is the path difference between S2P and S1P. Now a glass slab is introduced in front of S2 then the number of fring between O and P will –
(A) Increase
(B) decrease
(C) Many increase or decrease depends upon ∆x
(D) *** constant
Correct option (D) ***** constant**
Explanation:
Due to introduction of glass slab, number of fring between two points *** constant because if n number of fring crosses point P, then same number of fring also crosses point O in same sence.
