+2 votes
in JEE by kratos

Segment of the tangent to the curve xy = c2 at the point (x′, y′) which is contained between the coordinate axes is bisected at the point –

(A) (–x′, y′)

(B) (y′, x′)

(C) (x'/2, y'/2)

(D) of these

1 Answer

+5 votes
by kratos
 
Best answer

Correct option (D) of these

Explanation:

Which meets the co-ordinate axes at A and B (say) then A = (2x′, 0), B = (0, 2y′)

Mid point of AB is (x′, y′)

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