Reduce the following Boolean expression using K-map:
H(U, V, W, Z) = ∑(0, 1, 4, 5, 6, 7, 11, 12, 13, 14, 15)
There are 2 Pair and 1 Octet that reduce as given below:
Pair-1(m0 + m1) reduces to U’V’W’
Pair-2(m11+ m15) reduces to UWZ
Octet (m4+ m5 + m6 + m7 + m12+ m13 + m14 + m15) reduces to V
Simplified Boolean expression for given K-map is F(U, V, W, Z) = U’V’W’ +’ UWZ + V
