Question

A cricketer hits a ball with a velocity 25 m/* at 60∘ above the horizontal. How far above the ground it passes over a fielder 50 m from the bat (assume the ball is struck very close to the ground) :

A) 8.2 m

B) 9.0 m

C) 11.6 m

D) 12.7 m

Answer 1

The correct option is (a) 8.2 m.

Explanation:

Here ball is hit by cricketer with velocity 25 m/*.

The angle of projection= 60o.

Horizontal component of velocity vs = 25 cos 60o = 12.5 m/*

Vertical component of velocity vy = 25 sin 60o = 12.5 √3 m/*.

Time taken by ball to cover 50 m distance

t = /vs = 50/12.5 = 4

Now the vertical distance covered by the ball is given by