Question

What is the speed of a particle when accelerated to 1.0 GeV when the particle is (a) proton (b) electron

Answer 1

(a) γ = 1 + T/m = 1 + 1, 000/940 = 2.064

β = (γ 2 − 1)1/2/γ = [(2.064)2 − 1]1/2/2.064 = 0.87

(b) γ = 1 + 1, 000/0.511 = 1, 958

β = [1, 9582 − 1]1/2/1, 958 = 0.999973