+2 votes
in JEE by kratos

The equation of motion of a particle moving on circular path (radius 200 m) is given by = 18 t + 3t2 – 2t3 where is the total distance covered from straight point in metres at the end of t seconds. The maximum speed of the particle will be-

(A) 15 m/sec

(B) 23 m/sec

(C) 19.5 m/sec

(D) 25 m/sec

1 Answer

+3 votes
by kratos
 
Best answer

Correct option (C) 19.5 m/sec

Explanation:

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