This is a two-phase state at a given pressure:
vf = 0.001 043 m3/kg, vg = 1.6940 m3/kg
From the definition of quality we get the masses from total mass, m, as
mf = (1 – x) m, mg = x m
The volumes are
Vf = mf vf = (1 – x) m vf, Vg = mg vg = x mg vg
So the volume fraction of vapor is
Notice that the liquid volume is only about 0.5% of the total. We could also have found the overall v = vf + xvfg and then V = m v
