+2 votes
in Physics by kratos

Why the following reactions can not proceed as strong interactions

(a) π− + p → K − + Σ+

(b) d + d →4 He + π0?

1 Answer

+1 vote
by kratos
 
Best answer

(a) In this reaction initially the total strangeness quantum number

Si = Sπ + Sp = 0 + 0 = 0, while for the final state

Sf = SK + SΣ = −1 + (−1) = −2

ΔS = −2. Therefore, the rule ΔS = 0 for strong interactions is violated.

(b) The total isospin for the initial state I = 0 + 0 = 0, while for the final state I = 0 + 1 = 1.

ΔI = 1. Therefore, the rule ΔI = 0 for strong interactions is violated.

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