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If u = x^2tan^-1(y/x) - y^2tan^-1(x/y), prove that ∂^2u/∂y∂x = (x^2 - y^2)/(x^2 + y^2)

+3 votes
in Class 12 by kratos

If u = x2tan-1(y/x) - y2tan-1(x/y), prove that ∂2u/∂y∂x = (x2 - y2)/(x2 + y2)

1 Answer

+4 votes
by kratos
 
Best answer

u = x2 tan–1 (y/x) – y2 tan–1 (x/y)

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