Question

A hydraulic cylinder of area 0.01 m2 must push a 1000 kg arm and shovel 0.5 m straight up. What pressure is needed and how much work is done?

Answer 1

F = mg = 1000 kg × 9.81 m/* 2

= 9810 N = PA

P = F/A = 9810 N/ 0.01 m2

= 981 000 Pa = 981 kPa

W = ⌡⌠F dx = F ∆x = 9810 N × 0.5 m = 4905 J