+2 votes
in Mathematics by kratos

Two hydraulic cylinders maintain a pressure of 1200 kPa. One has a cross sectional area of 0.01 m2 the other 0.03 m2. To deliver a work of 1 kJ to the piston how large a displacement (V) and piston motion H is needed for each cylinder? Neglect Patm.

1 Answer

+5 votes
by kratos
 
Best answer

W = ∫ F dx = ∫ P dV = ∫ PA dx = PA* H = P∆V

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