A linear spring, F = ks (x − x0), with spring constant ks = 500 N/m, is stretched until it is 100 mm longer. Find the required force and work input.
F = ks (x - x0) = 500 x 0.1 = 50 N
W = ∫F dx = ∫ks (x - x0)d(x - x0) = ks (x - x0) 2/2
= 500 N/m x (0.12/2) m2 = 2.5 J
