The current I though a rod of a certain metallic oxide is given by I = 2V5/2, where V is the potential difference across it. The rod is connected in series with a resistance to a 6V battery of negligible internal resistance. What value should the series resistance have so that:
(i) the current in the current is 0.44
(ii) the power dissipated in the rod is twice that dissipated in the resistance.
