+3 votes
in Mathematics by kratos

Two springs with same spring constant are installed in a massless piston/cylinder with the outside air at 100 kPa. If the piston is at the bottom, both springs are relaxed and the second spring comes in contact with the piston at V = 2 m3. The cylindercontains ammonia initially at −2°C, x = 0.13, V = 1 m3, which is then heated until the pressure finally reaches 1200 kPa. At what pressure will the piston touch the second spring? Find the final temperature and the total work done by the ammonia.

1 Answer

+1 vote
by kratos
 
Best answer

State 1: P = 399.7 kPa

v = 0.00156 + 0.13×0.3106 = 0.0419 At bottom state 0: 0 m3, 100 kPa State 2: V = 2 m3 and on line 0-1-2 Final state 3: 1200 kPa, on line segment 2.

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