A 1 kg steel *** contains 1 kg liquid water both at 15°C. It is now put on the stove where it is heated to the boiling point of the water.

Question 1

A 1 kg steel *** contains 1 kg liquid water both at 15°C. It is now put on the stove where it is heated to the boiling point of the water. Neglect any air being heated and find the total amount of energy needed.

Question 2

Energy Eq U2 − U1= 1Q2 − 1W2

The steel does not change volume and the change for the liquid is minimal, so 1W2 ≅ 0.

kratos · Answer 1 · 2020-08-25T07:12:55+0000

Energy Eq U2 − U1= 1Q2 − 1W2

The steel does not change volume and the change for the liquid is minimal, so 1W2 ≅ 0.

A 1 kg steel *** contains 1 kg liquid water both at 15°C. It is now put on the stove where it is heated to the boiling point of the water.

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A 1 kg steel *** contains 1 kg liquid water both at 15°C. It is now put on the stove where it is heated to the boiling point of the water.

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