In a satellite, if the time ** of revolution is T, then kinetic energy will be proportional to :
(a) 1 /T3
(b) T −2 ⁄ 3
(c) 1 /T
(d) 1 /T2
Correct option (b) T −2 ⁄ 3
Explanation:
For a satellite to revolve in a circular orbit, kinetic energy = potential energy
Now according to Kepler’* law, we have
or K ∝ T − 2 ⁄ 3