+3 votes
in Mathematics by kratos

The filament of a 240V metal-filament lamp is to be constructed from a wire having a diameter of 0.02mm and a resistivity at 20°C of 4.3μΩ-cm. If α = 0.005/°C, what length of filament is necessary if the lamp is to dissipate 60 watts at a filament tempt. of 2420°C?

1 Answer

+2 votes
by kratos
 
Best answer

Electric power generated = I2R watts = V2/R watts

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