Question

A water-filled reactor with volume of 50 ft3 is at 2000 lbf/in.2, 560 F and placed inside a containment room,The room is well insulated and initially evacuated. Due to a ***, the reactor ruptures and the water fills the containment room. Find the minimum room volume so the final pressure does not exceed 30 lbf/in.2.

Answer 1

C.V.: Containment room and reactor.

Mass: m2 = m1 = Vreactor/v1 = 50/0.02172 = 2295.7 lbm

Energy m(u2 - u1) = 1Q2 - 1W2 = 0

⇒ u2 = u1 = 552.5 Btu/lbm

State 2: 30 lbf/in.2, u2 < ug ⇒ 2 phase

u = 552.5 = 218.48 + x2 869.41

⇒ x2 = 0.3842

v2 = 0.017 + 0.3842 x 13.808 = 5.322 ft3/lbm

V2 = mv2 = 2295.7 x 5.322 = 12218 ft3