C.V. R-22. Control mass goes through process: 1 -> 2 -> 3 As piston floats pressure is constant (1 -> 2) and the volume is constant for the second part (2 -> 3).
So we have: v3 = v2 = 2 × v1
State 3: (P,T) v3 = 0.2959 ft3/kg,
u3 = h - Pv = 117.0 - 200 x 0.2959 x 144/778
= 106.1 Btu/lbm