Question

Stephan’* reaction is reduction of :

(a) acyl halide in the presence of Pb/BaSO4

(b) alkyl isocyanide with Na and alcohol

(c) alkyl cyanide with SnCl2 and HCl

(d) alkyl cyanide with LiAlH4

Answer 1

Correct option (c) alkyl cyanide with SnCl2 and HCl

Explanation:

Stephan’* reaction is the reduction of alkyl cyanide with SnCl2 and HCl