+1 vote
in Mathematics by kratos

A cylinder has 0.1 kg air at 25°C, 200 kPa with a 5 kg piston on top. A valve at the bottom is opened to let the air out and the piston drops 0.25 m towards the bottom. What is the work involved in this process? What happens to the energy?

1 Answer

+6 votes
by kratos
 
Best answer

If we neglect acceleration of piston then P = C = pequilibrium

W = P ∆V

To get the volume change from the height we need the cylinder area. The force balance on the piston gives.

The air that *** inside has not changed state and therefore not energy. The work leaves as flow work Pv ∆m.

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