The molality of 1 litre solution of 93% H2SO4 (w/v) having density 1.84 g/ml is :
(a) 1.043 m
(b) 0.143 m
(c) 10.43 m
(d) none of these
Correct option (c) 10.43 m
Explanation:
93% H2SO4 (w/v) means 93 g. of H2SO4 is present in 100 c.c. of solution. Since vol. of solution = 1000 ml
∴ Amount of H2SO4 = 930 gper 1000 ml