+3 votes
in Chemistry by kratos

The molality of 1 litre solution of 93% H2SO4 (w/v) having density 1.84 g/ml is :

(a) 1.043 m

(b) 0.143 m

(c) 10.43 m

(d) none of these

1 Answer

+1 vote
by kratos
 
Best answer

Correct option (c) 10.43 m

Explanation:

93% H2SO4 (w/v) means 93 g. of H2SO4 is present in 100 c.c. of solution. Since vol. of solution = 1000 ml

∴ Amount of H2SO4 = 930 gper 1000 ml

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