+2 votes
in JEE by kratos

An electric light rated at 110V and 60 W is connected to a 120 V dry cell. The internal resistance of the battery is 60Ω. Will the light **** at full power when connected in this way?

1 Answer

+2 votes
by kratos
 
Best answer

The resistance of the bulb is R = V2/N = 202 ohms. The current flowing in the circuit consiting of the bulb and the battery is

i.e., 17V lower than the voltage required for the normal operation of the bulb. The bulb will not **** with its full incandescence. This result could have also been obtained by comparing the current flowing in the circuit of the battery to the current required for the normal incandescence of the bulb, the latter being I = N/V.

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