Question

The length of a thin bar magnet is 10 cm, the strength of the poles being 50 e.m.u. Determine the force acting on a unit north pole at a point A lying on the perpendicular to the magnet axis at its centre. Point A is at a distance of 10 cm from the axis. Consider the poles to be point poles.

Answer 1

Explanation:

The poles of the magnet act with forces F1 and F2 in the directions shown in Fig. 300. We have

F1 = F2 = 4m/5l2.

The position and magnitude of the resultant is readily found from the geometry of the vectors.