CV H2O out to the source, both 1Q2 and 1W2
State 1: Compressed liquid use saturated liquid at same T:
v1 = 0.001002 m3/kg; u1 = 83.94 kJ/kg; s1 = 0.2966 kJ/kg K
State 2: sup. vap.
v2 = 0.35411 m3/kg
u2 = 3124.3 kJ/kg;
s2 = 7.7621 kJ/kg K
W2 = (1000 + 150) 1 (0.35411 - 0.001002) = 203 kJ
1Q2 = 1(3124.3 - 83.94) + 203 = 3243.4 kJ
m(s2 - s1) = 1(7.7621 - 0.2968) = 7.4655 kJ/K
1Q2 / Tsource = 3.7146 kJ/K (for source Q = -1Q2
1S2 gen = m(s2 - s1) − 1Q2 / TSOURCE = ∆Stotal
= ∆SH2O + ∆Ssource = 7.4655 - 3.7146 = 3.751 kJ/K
Remark: This is an external irreversible process (delta T to the source)