Saturated water vapor at 20 psia is compressed to 60 psia in a reversible adiabatic process. Find the change in v and T.
Process adiabatic: dq = 0
Process reversible: dsgen = 0
Change in : ds = dq/T + dsgen = 0 + 0 = 0 thus is constant
T1 = 227.96 F, v1 = 20.091 ft3/lbm, s1 = 1.732 Btu/lbm R at 60 psia and * = s1 = 1.732 Btu/lbm R
