+1 vote
in Chemistry by kratos

A sample of clay was partially dried and then analysed to 50% silica and 7% water. The original clay contained 12% water. Find the percentage of silica in the original sample.

1 Answer

+6 votes
by kratos
 
Best answer

In the partially dried clay the total percentage of silica + water = 57%. The rest of 43% must be some.

impurity. Therefore the ratio of wts. of silica to impurity = 50/43. This would be true in the original sample of silica.

The total percentage of silica + impurity in the original sample is 88. If x is the percentage of silica,

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