Solution: consider the point of intersection of AD and BE as O.
now as BAD=30 and ABE is 60
therefore AOB=90.
also we know that median divides a triangle into two equal areas.
area of ABD=area of ADC
also O is centroid.
therefore AO=(2*4/3)=8/3
sin(60)=AO/AB
AB=16/(3*√3)
Now you know AD,AB and angle between the two i.e. 30
so area(ABD) =1/2ABADsin θ= 16/(3√3)
(θ=30)
therefore, the total area =2(area(ABD))
=32/(3√3) sq. unit
