Calculate the second law efficiency of the coflowing heat exchanger has one line with 0.25 kg/* oxygen at 17°C, 200 kPa entering

Question 1

Calculate the second law efficiency of the coflowing heat exchanger has one line with 0.25 kg/ oxygen at 17°C, 200 kPa entering and the other line has 0.6 kg/ nitrogen at 150 kPa, 500 K entering with an ambient at 17°C.

Question 2

C.V. Heat exchanger, steady 2 flows in and two flows out.

First solve for the exit temperature

C.V. Heat exchanger, steady 2 flows in and two flows out.

The second law efficiency for a heat exchanger is the ratio of the availability gain by one fluid divided by the availability drop in the other fluid. We thus have to find the change of availability in both flows. For each flow availability is include mass flow rate as in Eq. For the oxygen flow:

kratos · Answer 1 · 2020-11-17T12:36:15+0000

C.V. Heat exchanger, steady 2 flows in and two flows out.

First solve for the exit temperature

C.V. Heat exchanger, steady 2 flows in and two flows out.

The second law efficiency for a heat exchanger is the ratio of the availability gain by one fluid divided by the availability drop in the other fluid. We thus have to find the change of availability in both flows. For each flow availability is include mass flow rate as in Eq. For the oxygen flow:

Calculate the second law efficiency of the coflowing heat exchanger has one line with 0.25 kg/* oxygen at 17°C, 200 kPa entering

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Calculate the second law efficiency of the coflowing heat exchanger has one line with 0.25 kg/* oxygen at 17°C, 200 kPa entering

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