The area of the region bounded by the parabola (y – 2)2 = x – 1, the tangent to the parabola at the point (2, 3) and the x-axis is
(a) 6
(b) 9
(c) 12
(d) 3
(b) : (y – 2)2 = x –1 differentiating w.r.t. x, we have 2(y –2)y′ = 1
The equation of the tangent to the parabola at (2, 3) is
