Two identical conducting spheres A and B carry charges Q and 2Q respectively. They are separated by a distance

Question 1

Two identical conducting spheres A and B carry charges Q and 2Q respectively. They are separated by a distance much larger than their diameters. A third identical conducting sphere C is uncharged. Sphere C is first touched to A, then to B, and finally removed. As a result, the electrostatic force between A and B, which was originally F, becomes:

Question 2

The initial force between the two charges separated by a distance d is F = 2kQ2/d2 . After touching, the charges become Q/2 and 5Q/4 and the force is 5kQ2/8d2 = 5F/16 .

kratos · Answer 1 · 2020-10-10T10:51:32+0000

The initial force between the two charges separated by a distance d is F = 2kQ2/d2 . After touching, the charges become Q/2 and 5Q/4 and the force is 5kQ2/8d2 = 5F/16 .

Two identical conducting spheres A and B carry charges Q and 2Q respectively. They are separated by a distance

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Two identical conducting spheres A and B carry charges Q and 2Q respectively. They are separated by a distance

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