+1 vote
in Class 10 by kratos

ABC is a triangle inscribed in a circle with centre O. Let α = ∠ BAC, where 45° < α < 90° Let β = ∠BOC. Which one of the following is correct?

a. cosβ = (1 - tan2α)/(1 + tan2α)

b. cosβ = (1 + tan2α)/(1 - tan2α)

c. cosβ = 2tanα/(1 + tan2α)

d. sinβ = 2sin2α

1 Answer

+6 votes
by kratos
 
Best answer

Correct option a. cosβ = (1 - tan2α)/(1 + tan2α)

Explanation:

cosβ = cos2α = (1 - tan2α)/(1 + tan2α)

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