Question

Four particles of masses m, 2m, 3m and 4m are kept in sequence at the corners of a square of side a. The magnitude of gravitational force acting on a particle of mass m placed at the centre of the square will be

(a) (24m2G/a2)

(b) (6m2G/a2)

(c) (4√2Gm2/a2)

(d) Zero

Answer 1

Correct option (c) (4√2Gm2/a2)

Explanation:

If two particles of mass m are placed x distance apart then force of attraction Gmm/x2 = F (Let) Now according to problem particle of mass m is placed at the centre (P) of square. Then it will experience four forces

[x = a/*√*2 = half of the diagonal of the square]