If α ,β are roots of the equation x2+ px - 1/2p2 = 0 ,∀p ∈ R - {0}, hen the minimum value of α4 + β4 is
(a) 2√2
(b) 2 –√ 2
(c) 2
(d) 2 + √2
Correct option (d) 2 + √2
Explanation:
α4 + β4 = (α2 + β2)2 - 2α2β2 = ((α + β)2 - 2α β)2 - 2 (α β)2
= (p2 + 1/p2)2 - 1/2p4 = p4 + 1/2p4 + 2
(p2 + 1/√2p2)2 + 2 + √2
∴ Min value is 2 + √2